3x^2-3/4x-1/2=0

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Solution for 3x^2-3/4x-1/2=0 equation: 


x in (-oo:+oo)

3*x^2-((3/4)*x)-(1/2) = 0

3*x^2+(-3/4)*x-1/2 = 0

3*x^2-3/4*x-1/2 = 0

DELTA = (-3/4)^2-(-1/2*3*4)

DELTA = 105/16

DELTA > 0

x = ((105/16)^(1/2)+3/4)/(2*3) or x = (3/4-(105/16)^(1/2))/(2*3)

x = ((105/16)^(1/2)+3/4)/6 or x = (3/4-(105/16)^(1/2))/6

x in { (3/4-(105/16)^(1/2))/6, ((105/16)^(1/2)+3/4)/6 }

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